0 votes

If you have 2 CSR matrices (X and Y) of different shapes, you can simply use **X!=Y** and it will return *True*.

If CSR matrices are of the same shape, **X!=Y** returns a matrix of the same shape with boolean elements. You can then use *numpy.where()* to check whether they are the same or different.

Here is an example with 3 matrices A, B, and C of the shape 4x4:

import numpy as np

from scipy.sparse import csr_matrix

def comare_csr_matrix(x, y):

if np.sum(x != y) == 0:

return 'Same Matrices'

else:

return 'Different Matrices'

if __name__ == "__main__":

row = np.array([0, 0, 1, 1, 2, 3, 3])

col = np.array([0, 3, 0, 2, 1, 2, 3])

data = np.array([1 for i in range(len(col))])

data1 = np.array([2 for i in range(len(col))])

A = csr_matrix((data, (row, col)), shape=(4, 4))

B = csr_matrix((data, (row, col)), shape=(4, 4))

C = csr_matrix((data1, (row, col)), shape=(4, 4))

print(comare_csr_matrix(A, B))

print(comare_csr_matrix(B, C))